Solve (x+2)/3x + (x-2)/2x = 3

In order to solve this equation we need to rearrange it to have all of the variables on one side of the equals sign and the constants on the other. We do this by multiplying each term by the denominator of one of the fractions. First we multiply each term by 3x to obtain x + 2 + 3x(x-2)/2x = 9x. There is an x on the top and bottom of the fraction term so we can simplify further to get x + 2 + 3x/2 -3 = 9x which when we collect like terms becomes 13x/2 = -1. Dividing both sides by 13/2 gives the answer: x = -2/13

AY
Answered by Annabel Y. Maths tutor

18445 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Here is a right-angled triangle (base = 8cm and height = 9cm) and a rectangle (length = 16cm). The area of the rectangle is 6 times the area of the triangle. Work out the width of the rectangle.


(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.


If f(x)=(x-2)^2, determine the gradient of the tangent to the curve f(x) at x=-2.


Find the value of 9^(-1/2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning