A golf ball is hit from horizontal ground with speed 10 m/s at an angle of p degrees above the horizontal. The greatest height the golf ball reached above ground level is 1.22m. Model the golf ball as a particle and ignore air resistance. Find p.

Initial horizontal speed of particle = 10cos(p) m/s. Initial vertical speed of particle = 10sin(p) m/s. ('U' in suvat.) There are no forces other than gravity acting on the particle so the vertical acceleration on the partical while it is moving upwars is -9.8 m/s2. ('A' in suvat.) The greatest height reached by the golf ball is 1.22m. ('S' in suvat.) At this point, the ball has a vertical velocity of 0 m/s ('V' in suvat) as it is not moving upwards or downwards. Using this information, obtained from the question, we find out p using the suvat equation V2 = U2+2AS. 02 = (10sin(p))2 +2(-9.8)(1.22) 100sin2 (p) -23.912=0 sin2(p) =0.23912 sin(p)=0.4889989... p=sin-1(0.488989...). p=29.3.

SR
Answered by Sachin R. Further Mathematics tutor

4194 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Prove by mathematical induction that 2^(2n-1) + 3^(2n-1) is divisible by 5 for all natural numbers n.


a) Show that d/dx(arcsin x) = 1/(√ (1-x²)). b) Hence, use a suitable trigonometric substitution to find ∫ (1/(√ (4-2x-x²))) dx.


Find the equation of the tangent to the curve y = exp(x) at the point ( a, exp(a) ). Deduce the equation of the tangent to the curve which passes through the point (0,1) .


When and how do I use proof by induction?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences