Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form

 x^3=1=e^2(pi)i

x=e^2(pi)ik/3

The three roots are

k=0    x=1 

k=1    x=e^2(pi)*i/3

k=-1   x=e^-2(pi)ik/3

AA
Answered by Anmol A. Further Mathematics tutor

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