Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form
x^3=1=e^2(pi)ik
x=e^2(pi)ik/3
The three roots are
k=0 x=1
k=1 x=e^2(pi)*i/3
k=-1 x=e^-2(pi)ik/3
AA
Answered by Anmol A. • Further Mathematics tutor
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