titration calculation: 35cm3 of Hydrochloric Acid reacts with 27.5cm3, 0.3mol/dm3 NaOH. What is the Concentration of the Hydrochloric Acid?

  1. Write out what you know:

    HCL - VOL: 35 --- CONC: (x) --- MOL: (x)
    NaOH - VOL: 27.5 --- CONC: 0.3 --- MOL: (x)

  2. Realise what you can work out - Mol of NaOH in this case
    Mol = Conc x (Vol/1000)
    so Mol = 0.3 x (27.5/1000)
    Mol = 0.00825

  3. Now you have all the Info for one substance and most importantly the moles of a substance.

  4. Mol Ratio is 1:1 unless the question says otherwise

  5. Rearrange Mol = Conc x (Vol/1000)
    to make Conc = Mol / (Vol/1000)
    Conc = 0.00825 / (35/1000)
    Conc = 0.235

    0.24mol/dm3 = Conc of HCL
Answered by Ghazn K. Chemistry tutor

4100 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

How do you describe the greenhouse effect?


Explain the trends in electronegativity in the periodic table


Describe how a metal conducts electricity


What are the differences between covalent bond and an ionic bond? And can you give an example of each?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences