titration calculation: 35cm3 of Hydrochloric Acid reacts with 27.5cm3, 0.3mol/dm3 NaOH. What is the Concentration of the Hydrochloric Acid?

  1. Write out what you know:

    HCL - VOL: 35 --- CONC: (x) --- MOL: (x)
    NaOH - VOL: 27.5 --- CONC: 0.3 --- MOL: (x)

  2. Realise what you can work out - Mol of NaOH in this case
    Mol = Conc x (Vol/1000)
    so Mol = 0.3 x (27.5/1000)
    Mol = 0.00825

  3. Now you have all the Info for one substance and most importantly the moles of a substance.

  4. Mol Ratio is 1:1 unless the question says otherwise

  5. Rearrange Mol = Conc x (Vol/1000)
    to make Conc = Mol / (Vol/1000)
    Conc = 0.00825 / (35/1000)
    Conc = 0.235

    0.24mol/dm3 = Conc of HCL
Answered by Ghazn K. Chemistry tutor

4054 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

What is the purpose of a catalytic converter, and what is the reaction equation of a process that it catalyses?


Explain the atomic structure of an Atom?


Describe how to find the concentration of an alkali using an acid of a known concentration.


Why is the Haber Process run at 450 °C instead of room temperature?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences