titration calculation: 35cm3 of Hydrochloric Acid reacts with 27.5cm3, 0.3mol/dm3 NaOH. What is the Concentration of the Hydrochloric Acid?
- Write out what you know:
HCL - VOL: 35 --- CONC: (x) --- MOL: (x)
NaOH - VOL: 27.5 --- CONC: 0.3 --- MOL: (x)
- Realise what you can work out - Mol of NaOH in this case
Mol = Conc x (Vol/1000)
so Mol = 0.3 x (27.5/1000)
Mol = 0.00825
- Now you have all the Info for one substance and most importantly the moles of a substance.
- Mol Ratio is 1:1 unless the question says otherwise
- Rearrange Mol = Conc x (Vol/1000)
to make Conc = Mol / (Vol/1000)
Conc = 0.00825 / (35/1000)
Conc = 0.235
0.24mol/dm3 = Conc of HCL
GK
Related Chemistry GCSE answers
All answers ▸How is the electronic structure of sodium different to chlorine?
What is an emulsion? and give some examples
What mass of carbon dioxide is produced from burning 100 grams of ethanol in oxygen according to this reaction: C2H5OH + 3 O2 --> 2 CO2 + 3 H2O
State the trends in reactivity of the group 1 and group 7 elements and explain the reasons why.