Solve x^2+8x-5 = 0 by completing the square.

x2 + 8x = (x + 4)2 - 16, so x2 + 8x - 5 = (x + 4)2 - 16 - 5 = (x + 4)2 - 21, so then (x + 4)- 21 = 0 (x + 4)= 21 -----> x + 4 = √21 -------> x = -4 + √21                               x = -4 - √21

Answered by Shadab J. Maths tutor

10169 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you rationalize the denominator of a fraction?


Solve algebraically the simultaneous equations x^2 + y^2 = 25, y – 3x = 13


A shape consists of a quarter circle (radius r = 4cm) attached to a triangle (side length = 4cm and hypotenuse = 5cm). This shape is surrounded by a square (side length 8cm). If the shape is coloured in, what is the area in the square that is uncoloured?


Solve (72x^3 - 18x)/(12x^2 - 6x) = 0 for x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences