fg(x) = 2(cx+5) + c
= 2cx+10+c [1 mark]
fg(x) = 6x+d. fg(x) = 2cx+10+c
6x = 2cx and d = 10+c [2 marks]
3 = c and therefore d = 13 [3 marks]
19648 Views
Internet Safety
Payment Security
Cyber
Essentials