Solve x^2 + 15x = - 50
-
x2 + 15 x + 50 = 0 (rearrange by adding 50 to both sides)
-
(x + 10)(x + 5) = 0 (factorise the quadratic equation)
-
x + 10 = 0 or x + 5 = 0 (for the above to equal zero, at least one of the bracketed terms must equal zero)
-
x = -10 or x = -5 (solving the two equations that result from step 3)
-
The solution is x = -10, x = -5
JS
Related Maths GCSE answers
All answers ▸[equ1] 3y − 6x = 3 [equ2] y y x 2 − x + 2 2 = 2
You are given that f(x) = cx + d and that f(0) = -6 and f(2) = 10. Find the values of c and d.
Find the equation of the straight line which passes through the point (0, 3) and is perpendicular to the straight line with equation y = 2x.
Find the equation of the line perpendicular to y=2x-1 that passes through (2,0)