Solve the simultaneous equations: 4x+5y = 38 , x-y = 5

Firstly number the two equations 1 and 2 for simplicity. To solve this we want to eliminate one of the variables, x or y, so we start by looking at the equations and seeing if we can add or subtract them from each other to get rid of one of the variables. From these equations it doesnt look like we can do this immediately. What we do now is multiply equation two (x-y=5) by 5, to get our new equation three : 5x-5y =25. REMEMBER to multiply the right hand side as well... Now we see we can add equation three to eqaution one and this removes y...we are left with 9x =63. Divide by 9 to get x=7. Now plug x = 7 into one of the original equations, for simplicity use equation two. And this gives us y=2

AA
Answered by Ali A. Maths tutor

4613 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do i solve quadratic equations?


5w -3 = 3w + 15


Factorise 2(x^2) +7x+3


Consider a right-angled triangle with an inside angle of 30° and a hypotenuse of 8cm. Calculate the length of the opposite side to the 30° angle.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning