Solve the simultaneous equations: 4x+5y = 38 , x-y = 5

Firstly number the two equations 1 and 2 for simplicity. To solve this we want to eliminate one of the variables, x or y, so we start by looking at the equations and seeing if we can add or subtract them from each other to get rid of one of the variables. From these equations it doesnt look like we can do this immediately. What we do now is multiply equation two (x-y=5) by 5, to get our new equation three : 5x-5y =25. REMEMBER to multiply the right hand side as well... Now we see we can add equation three to eqaution one and this removes y...we are left with 9x =63. Divide by 9 to get x=7. Now plug x = 7 into one of the original equations, for simplicity use equation two. And this gives us y=2

Answered by Ali A. Maths tutor

3995 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

if x^2 + 9x + 20 = 0, what are the possible values of x?


I need help understanding simultaneous equations with more than two variables, can you please help?


Simplify 2a+6b-a+2b+3a


A 4 digit number is picked. It's second digit is a prime number, it must be even and it must be greater than 5000. How many possible numbers can be picked?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences