Solve: a) 5t + 17 = 2 b) x^3 - 25 = 103 - x^3

a) Solving for t:
We isolate our unknown t on one side, to leave the factors of t on one side and the numbers on the other:
-1st step: substract 17 from both sides --> 5t = -15
-2nd step: divide by 5 on both sides --> t = -3

b) Solving for x: We now isolate the power of x on one side:
-1st step: add x^3 on both sides --> 2*(x^3)-25=103

-2nd step: add 25 on both sides --> 2*(x^3) = 128

-3rd step: divide by two on both sides --> x^3 = 64

  • Finally to get rid of the exponent, we take the cube root on both sides of the expression --> x = 4
Answered by Luis C. Maths tutor

3133 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations algebraically: y = x+19 AND y = x^2 + 4x +1.


Factorise fully 6xyz + 24x^2yz + 18xy^3z^2


What is red shift?


Solve the simultaneous equations x^2 + y^2 =13 and x= y - 5.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences