Solve: a) 5t + 17 = 2 b) x^3 - 25 = 103 - x^3

a) Solving for t:
We isolate our unknown t on one side, to leave the factors of t on one side and the numbers on the other:
-1st step: substract 17 from both sides --> 5t = -15
-2nd step: divide by 5 on both sides --> t = -3

b) Solving for x: We now isolate the power of x on one side:
-1st step: add x^3 on both sides --> 2*(x^3)-25=103

-2nd step: add 25 on both sides --> 2*(x^3) = 128

-3rd step: divide by two on both sides --> x^3 = 64

  • Finally to get rid of the exponent, we take the cube root on both sides of the expression --> x = 4
LC

Related Maths GCSE answers

All answers ▸

Find the intersection point between the equations y=4x+7 and 3y=12x+21


If x:y = 7:4 and x+y = 88 , work out the value of x–y.


Solve 3x+7=8


Solve the simultaneous equations: (a) y - 2x = 6; (b) y+2x = 0.