Calculate the value of both x and y using the following 2 equations: 3x - 2y = 12 (1) and x - y = 3 (2)

Process of elimination:

Multiply equation 2 by 3 to get the same coefficent in front of x:  3x - 3y = 9  (3)

Subtract eq 3 from eq 1 to get:  y = 3

Substitutute our value for y into eq 2 for simplicity: x - 3 = 3  therefore x = 6

Process of substitution: Add y to the right hand side of equation 2 to get: x = 3 + y

Substitute this expression of x into equation 1 to eliminate x:  3(3+y) - 2y = 12 

Expand and simplify: 9 + y = 12 therefore y = 3

Substitute this value of y into equation 2 and solve for x: x - 3 = 3 so x = 6

Answered by Hamza M. Maths tutor

7803 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve ((x+2)/3x) + ((x-2)/2x) = 3


A rectangle has an area of 20 cm2. Its length and width are enlarged by scale factor 3. Find the area of the enlarged rectangle.


The equation of a quadratic curve is y=x^2+ax+b. The points (6,-4) and (4,-6) lie on this curve. Find the co-ordinates of the turning point of the curve.


If a student wishes to have a ratio of 2:7 red pens to yellow pens in their pencil case: a) if they have 50 pens total what is the maximum amount they can carry with them b) if they have 18 red and 31 yellow what is the maximum amount they can carry


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences