What is the turning point on the curve f(x) = 2x^2 - 2x + 4

df/dx = 4x - 2

turning point when differential = 0 

==>

4x = 2 hence;  x = 0.5

When x = 0.5 f(x) is equal to (substitute) 3.5

hence the turning point is at (0.5,3.5)

DT
Answered by David T. Maths tutor

5829 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the set of values of k for which x^2 + 2x+11 = k(2x-1)


Find dy/dx in terms of t for the curve defined by the parametric equations: x = (t-1)^3, y = 3t - 8/t^2, where t≠0


How to express (4x)/(x^2-9)-2/(x+3)as a single fraction in its simplest form.


What is a derivative and how do we calculate it from first principles?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning