What is the turning point on the curve f(x) = 2x^2 - 2x + 4

df/dx = 4x - 2

turning point when differential = 0 

==>

4x = 2 hence;  x = 0.5

When x = 0.5 f(x) is equal to (substitute) 3.5

hence the turning point is at (0.5,3.5)

DT
Answered by David T. Maths tutor

5787 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is differentiation and how do I do it?


How do I find the equation of a tangent to a given point on a curve?


Solve the inequality x^2 - 9 > 0


Find the integral of the following equation: y = cos^2(x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning