Find the general solution of the second order differential equation: y''+2y'-3 = 0
This is a homogeneous second order equation with constant coefficients, so all we need to do is find the complementary function: We write: m2+2m-3=0 which has solutions m=1 or m=-3 We have two real solutions, so we get two exponential terms in the general solution: ex and e-3x This gives the general solution (putting in arbitrary constants): y = Aex+Be-3x
MD
Answered by Matthew D. • Further Mathematics tutor
6596 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Write (1+2i) /(2-i) in form x+iy
How do you find the general solution of a second order differential equation?
How do I find and plot the roots of a polynomial with complex roots on an Argand diagram? e.g. f(z) =z^3 -3z^2 + z + 5 where one of the roots is known to be 2+i
Solve the inequality x/(x+2) ≤ 4/(x-3) for x ≠ -2 or 3