Find the general solution of the second order differential equation: y''+2y'-3 = 0
This is a homogeneous second order equation with constant coefficients, so all we need to do is find the complementary function: We write: m2+2m-3=0 which has solutions m=1 or m=-3 We have two real solutions, so we get two exponential terms in the general solution: ex and e-3x This gives the general solution (putting in arbitrary constants): y = Aex+Be-3x
MD
Answered by Matthew D. • Further Mathematics tutor
6650 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Prove that ∑(1/(r^2 -1)) from r=2 to r=n is equal to (3n^2-n-2)/(4n(n+1)) for all natural numbers n>=2.
By using an integrating factor, solve the differential equation dy/dx + 4y/x = 6x^-3 (6 marks)
Find the stationary points of the function z = 3x(x+y)3 - x3 + 24x
Understanding differentiation from first principle.