Find the general solution of the second order differential equation: y''+2y'-3 = 0
This is a homogeneous second order equation with constant coefficients, so all we need to do is find the complementary function: We write: m2+2m-3=0 which has solutions m=1 or m=-3 We have two real solutions, so we get two exponential terms in the general solution: ex and e-3x This gives the general solution (putting in arbitrary constants): y = Aex+Be-3x
MD
Answered by Matthew D. • Further Mathematics tutor
6691 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸What is sin(x)/x for x =0?
What are imaginary numbers and why do we use them?
Using a Suitable substitution or otherwise, find the differential of y= arctan(sinxcosx), in terms of y and x.
solve 3sinh^2(2x) + 11sinh(2x) = 4 for x, giving your answer(s) in terms of the natural log.