Integrate the following between 0 and 1: (x + 2)^3 dx

Initially, we must recognise the simplest way to integrate this equation is using the 'reverse chain rule' method. 

This means raising the value of the power, in this case '3', by one, and then dividing by the new value of the power (which is four). This gives the integral to be 1/4 * (x + 2)^4 + c where c is a constant. We can check that this is correct by differentiating to give the original equation.

This is a definite integral, as there are bounds, so we must evaluate this new equation between 1 and 0: 

[1/4 * (x + 2)^4 + c] between 1 and 0 gives: 1/4[((1+2)^4 + c) - ((0 + 2)^4 + c)] = 1/4[81 - 16] = 16.25

WE
Answered by Will E. Maths tutor

3137 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I find a stationary point on a curve and work out if it is a maximum or minimum point?


differentiate with respect to x: (x^3)(e^x)


Simplify the following C4 question into it's simplest form: (x^4-4x^3+9x^2-17x+12)/(x^3-4x^2+4x)


Prove by contradiction that there is an infinite number of prime numbers.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences