Find the first 4 term of the binomial expansion (2-4x)^5

Step 1: Look at formula in formula booklet provided and write out formula.

Formula: (a+b)n= annc1an-1b + nC2an-1b2+...+nCran-rb

In this question our a=2 our b=-4x and our n=5

Therefore our first 4 terms are:

4+ 524(-4x) + 1023(-4x)2 + 1022(-4x)3

= 32 - 320x +1280x2 -2560x3

Answered by Charlie R. Maths tutor

4097 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

i) Simplify (2 * sqrt(7))^2 ii) Find the value of ((2 * sqrt(7))^2 + 8)/(3 + sqrt(7)) in the form m + n * sqrt(7) where n and m are integers.


Integrate (12x^5 - 8x^3 + 3)dx giving the terms of the answer in the simplest terms


Prove that sqrt(2) is irrational


What is the chain rule and how is it used?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences