Find the equation of a straight line that passes through the coordinates (12,-10) and (5,4). Leaving your answer in the form y = mx + c

Finding the gradient (m): The gradient is the change in y-axis over the change in x-axis Δy = -10-4= -14        Δx = 12-5=7 Δy/Δx = -14/7 = -2 Accumilating the equation: The equation of a straight line can be deduced by a simple formula y- ya = m(x- xa)      where a is a coordinate which lies on the lie.

The equation: y - 4 = -2(x - 5) y - 4 = -2x + 10

Therefore the equation of the line: y= -2x+14

Martin M. avatar
Answered by Martin M. Maths tutor

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