Differentiate arctan of x with respect to x.

Say arctan of x is equal to a value y. Now take the tangent of both sides; x now equals tan of y! Easy from here, differentiate both sides wrt x. Now 1 equals sec^2y dy/dx, and you can rearrange to find dy/dx. To simplify, use the trig identity tan^y+1=sec^y, to get 1/1+x^2 is dy/dx.

Related Further Mathematics A Level answers

All answers ▸

How do you prove the formula for the sum of n terms of an arithmetic progression?


Solve for z in the equation sin(z) = 2


Prove by induction that the sum from r=1 to n of (2r-1) is equal to n^2.


Using de Moivre's theorem demonstrate that "sin6x+sin2x(16(sinx)^4-16(sinx)^2+3)"


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences