Make s the subject of the equation: 4st + 8 = 5r

To begin this question, we want to isolate the term containing the s, i.e. have the term containing the s by itself on one side of the equality. We do this by subtracting 8 from both sides. 4st = 5r - 8 To make s the subject of this equation, we want to undo whatever has been done to it. We notice that the s has been multiplied by 4 and by t, so, to counteract this, we divide both sides by 4 and t. s = (5r - 8) / 4t

SW
Answered by Sophie W. Maths tutor

3713 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

a.) simplify and expand (x+3)(2x+5) b.) differentiate (x+3)(2x+5) c.) where does this function intercept the x and y axis? d.) does this function have any turning points? if so where?


Expand and simplify (x+6)(x+4)


factorise 2x^2 +10x


Solve the inequality x^2 < -8x + 9


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning