Make s the subject of the equation: 4st + 8 = 5r

To begin this question, we want to isolate the term containing the s, i.e. have the term containing the s by itself on one side of the equality. We do this by subtracting 8 from both sides. 4st = 5r - 8 To make s the subject of this equation, we want to undo whatever has been done to it. We notice that the s has been multiplied by 4 and by t, so, to counteract this, we divide both sides by 4 and t. s = (5r - 8) / 4t

SW
Answered by Sophie W. Maths tutor

3500 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that the difference of the square of two consecutive odd numbers is always a multiple of 8. [OCR GCSE June 2017 Paper 5]


A car costs £1200 in a sale. It was reduced by 20%. What was the original price?


Work out the nth term of the sequence 3, 7, 11, 15, ...


The probability a student in a school wears glasses is 3/7. There are 164 students who DON'T wear glasses. Find the number that wear glasses.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning