There is a point between the Moon and the Earth where the gravitational attractions are equal and opposite. How much further is this point from the Earth than the Moon

Using the formula for gravitational attraction between the Moon/Earth and a test mass, m. We determine FE = (G*ME m)/(rE2 ), FM = (GMM*m )/ (rM2). Setting these two forces equal to each other and rearranging gives us the formula: rM2 = (MM/ME ) * rE2. Taking the square root of both sides, and noting the distances, r, should always be positive we get distance from the Earth is sqrt(MM/ME). 

PD
Answered by Paul D. Physics tutor

7534 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

What is the De Broglie wavelength of an electron given it has a kinetic energy of 1 eV? You are given the mass of an electron is 9.11x10^-31 kg and Planck's constant is 6.63x10^-34


The LHC accelerates protons to a speed of 0.999999991c around a 27km ring. Due to relativistic effects, their mass increases. Given that the magnetic fields used are 8T, calculate this mass. What is the total energy of an LHC beam containing 3e14 protons?


Describe how the average density of matter in the universe affects its ultimate fate?


A ball with radius 10cm is filled with an ideal gas at pressure 2*(10)^5Pa and temperature 300K. The volume of the gas is changed at constant pressure so that the radius of the ball is reduced with 1cm. Find the amount of gas and the new temperature


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning