Given that 2-3i is a root to the equation z^3+pz^2+qz-13p=0, show that p=-2 and q=5.
Substitute 2-3i into equation using part i (2-3i)3=-46-9i. -46-9i+p(-5-12i)+q(2-3i)-13p=0. -46-18p+2q-9i-12pi-3iq=0. Real: -46-18p+2q=0 and Imaginary: -9-12p-3q=0. p=-2, q=5
WN
Related Maths A Level answers
All answers ▸Differentiate ln(x)/x
Show that tan(x) + cot(x) = 2cosec(2x)
The curve C has the parametric equations x=4t+3 and y+ 4t +8 +5/(2t). Find the value of dy/dx at the point on curve C where t=2.
Given that the binomial expansion of (1 + kx) ^ n is 1 - 6x + 30x^2 + ..., find the values of n and k.