The complex conjugate of 2-3i is also a root of z^3+pz^2+qz-13p=0. Find a quadratic factor of z^3+pz^2+qz-13p=0 with real coefficients and thus find the real root of the equation.

z-2+3i times z-2-3i = z2-4z+13. z3-2z2+5z+26 divided by z2-4z+13 = z+2. Therefore the real root is z=-2.

WN
Answered by William N. Maths tutor

5875 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the derivative of f(x)= ln(|sin(x)|). Given that f(x) has a value for all x, state why the modulus is required.


What is integration?


let y=6x^-0.5+2x+1, find dy/dx.


Express 6cos(2x)+sin(x) in terms of sin(x). Hence solve the equation 6cos(2x) + sin(x) = 0, for 0° <= x <= 360°.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning