Try y=Aebx diffrentiate this (dy/dx = Abebx) and sub into 2dy/dx -5y = 0 to find complementary function. 2Abebx - 5Aebx = 0 2b - 5 = 0 b = 2.5 Find the particular integral using trial solution y = Cx+D, dy/dx = C 2C - 5(Cx+D) = 10x Separate constants and x terms to solve for C and D -5Cx = 10x C=-2 2C - 5D = 0 -4 - 5D = 0 D=-4/5 Combine these two solutions to find the general solution. The answer contains a constant, more information is needed to find A y = Ae2.5x - 2x - 4/5