Ignoring air resistance, use an energy argument to find the speed of a ball when it hits the ground if it is dropped from 50m, where m is the mass of the ball.
Original energy: GPE=509.81m KE=0 Final energy: GPE=0 KE=(1/2)mv2 Therefore (1/2)mv2 = 50m9.81 . The m cancels and simplifying the equation we are left with v2 = 5029.81, therefore v = 31 ms-1
ZT
Related Physics A Level answers
All answers ▸The mercury atoms in a fluorescent tube are excited and then emit photons in the ultraviolet region of the elecrtomagnetic spectrum. Explain how the mercury atoms become excited.
What do I need to do for full marks on the question "describe an everyday circumstance where resonance occurs (4 marks)"?
A ball with radius 10cm is filled with an ideal gas at pressure 2*(10)^5Pa and temperature 300K. The volume of the gas is changed at constant pressure so that the radius of the ball is reduced with 1cm. Find the amount of gas and the new temperature
Why is the centripetal force necessary for circular motion?