Ignoring air resistance, use an energy argument to find the speed of a ball when it hits the ground if it is dropped from 50m, where m is the mass of the ball.
Original energy: GPE=509.81m KE=0 Final energy: GPE=0 KE=(1/2)mv2 Therefore (1/2)mv2 = 50m9.81 . The m cancels and simplifying the equation we are left with v2 = 5029.81, therefore v = 31 ms-1
ZT
Related Physics A Level answers
All answers ▸How do I find the half-life of radioactive isotope?
A car moves from rest and accelerates uniformly at 4m/s/s, how far will it have traveled after 10 seconds?
Two trains are heading in opposite directions on the same track. Train X has a mass of 16000kg and a speed of 2.8m/s. Train Y has a mass of 12000kg and a speed of 3.1m/s. At what speed do the joined trains move off together immediately after the collison?
I dont really understand the Rutherford experiment