Ignoring air resistance, use an energy argument to find the speed of a ball when it hits the ground if it is dropped from 50m, where m is the mass of the ball.
Original energy: GPE=509.81m KE=0 Final energy: GPE=0 KE=(1/2)mv2 Therefore (1/2)mv2 = 50m9.81 . The m cancels and simplifying the equation we are left with v2 = 5029.81, therefore v = 31 ms-1
ZT
Related Physics A Level answers
All answers ▸Derive an expression to show that for satellites in a circular orbit T^2 ∝ r^3 where T is the period of orbit and r is the radius of the orbit.
When catching a ball, a cricketer moves his hands for a short distance in the direction of travel of the ball as it makes contact with his hands. Explain why this technique results in less force being exerted on the cricketer's hands
Explain how and why the diffraction pattern of electrons passing through a slit depends on their momentum.
What is a potential divider?