How would I differentiate a function such as f(x)=x^3(e^(2x))?

Here, f(x)=x3e2x is a function consisting of two functions multiplied together, so we need to use the product rule. The product rule is as follows: where f(x)=u(x)v(x), f'(x)=u(x)v'(x)+u'(x)v(x). The first step involves identifying the two functions that are multiplied together, and representing them by u and v. So, let u(x)=x3 and v(x)=e2x. Now, we must find u'(x) and v'(x). u'(x)=3x2 (from Core 1: multiply by the power, then subtract 1 from the power) and v'(x)=2e2x  (from using the chain rule). Then, substitute u(x), v(x), u'(x) and v'(x) into our product rule formula, giving f'(x)=x. 2e2x + 3x.e2x     If you wish to simplify this, you can do so by taking out a common factor of x2e2x from each term: f'(x)=x2e2x(2x+3)

LB
Answered by Lauren B. Maths tutor

3354 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Shower-cleaner liquid is sold in spray bottles. The volume of liquid in a bottle may be modelled by a normal distribution with mean 955 ml and a standard deviation of 5 ml. Determine the probability that the volume in a particular bottle is:


Find the equation of the normal to the curve y=2x^3 at the point on the curve where x=2. Write in the form of ax+by=c.


Differentiate the following: 5x^3


Given that cos(x) = 1/4, what is cos(2x)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning