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A geometric progression has first term 3 and second term -6. State the value of the common ratio.

3/-6 = -2

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How do I differentiate y=(4+9x)^5 with respect to x?

By forming and solving a quadratic equation, solve the equation 5cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2pi, giving the values of x in radians to three significant figures.

How to solve polynomials

Given df/dx=2x+3 and the graph goes through (1,1), what is the function f?

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A geometric progression has first term 3 and second term -6. State the value of the common ratio.

Related Maths A Level answers

How do I differentiate y=(4+9x)^5 with respect to x?

By forming and solving a quadratic equation, solve the equation 5cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2pi, giving the values of x in radians to three significant figures.

How to solve polynomials

Given df/dx=2x+3 and the graph goes through (1,1), what is the function f?

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A geometric progression has first term 3 and second term -6. State the value of the common ratio.

Related Maths A Level answers

How do I differentiate y=(4+9x)^5 with respect to x?

By forming and solving a quadratic equation, solve the equation 5*cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2*pi, giving the values of x in radians to three significant figures.

How to solve polynomials

Given df/dx=2x+3 and the graph goes through (1,1), what is the function f?

We're here to help

Company Information

Popular Requests

CLICK CEOP

MyTutor is part of the IXL family of brands:

IXL

Rosetta Stone

Wyzant

Education.com

Vocabulary.com

Emmersion

Thesaurus.com

Dictionary.com

SpanishDictionary.com

FrenchDictionary.com

Ingles.com

ABCya

© 2025 by IXL Learning

By forming and solving a quadratic equation, solve the equation 5cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2pi, giving the values of x in radians to three significant figures.