Solve the pair of simultaneous equations; (1) y + 4x + 1 = 0, (2) y^2 + 5x^2 + 2x = 0 .

Rearrage equation (1) to make y the subject of the formula. This gives y = -4x -1 .

Substitute this value of y into equation (2). This gives (-4x -1)^2 +5x^2 +2x = 0 . 

Expanding out the brackets gives 16x^2 + 8x + 1 + 5x^2 +2x =0 .

Collecting all the like terms gives 21x^2 +10x + 1 = 0 .

Factorising this equation gives (7x + 1)(3x + 1) = 0 which means x = -1/7, -1/3 . 

Substituting these x values back into (1) implies that y = - 3/7, 1/3 .

MG
Answered by Melanie G. Maths tutor

7050 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate the equation 4x^5 + 2x^3 - x + 2


Use logarithms to solve the equation 3^(2x+1) = 4^100


Given f(x) = (x^4 - 1) / (x^4 + 1), use the quotient rule to show that f'(x) = nx^3 / (x^4 + 1)^2 where n is an integer to be determined.


How do I solve x^2 > 6 - x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning