In the Photoelectric effect, Why does increasing the light intensity have no effect on the energy of the electron emitted?

The equation to calculate the energy of an emitted electron is: E = hf - φ, where E is the energy of the electron emitted, is the Planck's constant, f is the frequency of the light and φ is the work function of the metal which is the minimum energy required to emit an electron. Here you can see that nothing is dependant on light intensity because the intensity is essentially the number of photons and does not increase nor decrease the energy of a single photon, therefore has no effect on the energy of an electron emitted. 

If the light has enough energy to emit a photon i.e. has a high enough frequency, then the light intensity will increase the probability of an electron being emitted from the metal.  

PK

Related Physics A Level answers

All answers ▸

This is a question on the photoelectric effect: For potassium, the work function is 3.65E-19J. Find the maximum wavelength of light that will cause photoelectrons to be emitted when shone onto potassium.


explain how a cyclotron produces a high energy electron


How do you work out the direction and strength of the force on a current carrying wire in a magnetic field?


A Positron has the same mass, but opposite charge to an electron. A Positron and electron are orbiting around each other separated by 1μm, in a stable circular orbit about their centre of mass, as a result of electrostatic attraction. Calculate the period