curve C with parametric equations x = 4 tan(t), y=5*3^(1/2)*sin(2t). Point P lies on C with coordinates (4*3^(1/2), 15/2). Find the exact value of dy/dx at the point P.

dy/dx = dy/dt *dt/dx (chain rule).

x=4tan(t) hence dx/dt = 4 sec2(t)

y = 531/2sin(2t) hence y'= 1031/2 cos(2t)

therefore dy/dx = 1031/2 cos(2t) / 4sec2(t). Since P is on point with x=431/2 we can duduce that t=π/3 and substituting t in dy/dx we get -531/2/16

HP
Answered by Harry P. Maths tutor

8057 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

(The question is too long so it's marked at the top of the answer space, sorry for any inconveniences)


Differentiate y=(x-1)^4 with respect to x.


The velocity of a car at time, ts^-1, during the first 20 s of its journey, is given by v = kt + 0.03t^2, where k is a constant. When t = 20 the acceleration of the car is 1.3ms^-2, what is the value of k?


(a) Express (1+4*sqrt(7))/(5+2*sqrt(7)) in the form a+b*sqrt(7), where a and b are integers. (b) Then solve the equation x*(9*sqrt(5)-2*sqrt(45))=sqrt(80).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning