curve C with parametric equations x = 4 tan(t), y=5*3^(1/2)*sin(2t). Point P lies on C with coordinates (4*3^(1/2), 15/2). Find the exact value of dy/dx at the point P.

dy/dx = dy/dt *dt/dx (chain rule).

x=4tan(t) hence dx/dt = 4 sec2(t)

y = 531/2sin(2t) hence y'= 1031/2 cos(2t)

therefore dy/dx = 1031/2 cos(2t) / 4sec2(t). Since P is on point with x=431/2 we can duduce that t=π/3 and substituting t in dy/dx we get -531/2/16

HP
Answered by Harry P. Maths tutor

8052 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

find dy/dx= x^2 +x^3


What is the equation of the normal line to the curve y = 3x^3 - 6x^2 at the point (1, 4)?


Differentiate y=(4x^2-1)^3


Find d/dx (ln(2x^3+x+8))


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning