curve C with parametric equations x = 4 tan(t), y=5*3^(1/2)*sin(2t). Point P lies on C with coordinates (4*3^(1/2), 15/2). Find the exact value of dy/dx at the point P.

dy/dx = dy/dt *dt/dx (chain rule).

x=4tan(t) hence dx/dt = 4 sec2(t)

y = 531/2sin(2t) hence y'= 1031/2 cos(2t)

therefore dy/dx = 1031/2 cos(2t) / 4sec2(t). Since P is on point with x=431/2 we can duduce that t=π/3 and substituting t in dy/dx we get -531/2/16

HP
Answered by Harry P. Maths tutor

8028 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve is defined by the parametric equations x = 3 - 4t, and y = 1 + 2/t. Find dy/dx in terms of t.


Find the derivative of the function f:(0,oo)->R, f(x)=x^x.


The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).


factorise x^3 + 3x^2 - 13x - 15


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning