How do you integrate y = 4x^3 - 5/x^2?
First we should look at the formula for integrating xn. The integral is (xn+1 / n+1) + C.
Let's break down our equation into two parts.
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The integral of 4x3 = 4(x3+1 / 3+1) = 4(x4 / 4) = x4
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The integral of -5/x2 = -5(x-2+1 / -2+1) = -5(x-1 / -1) = 5(x-1) = 5/x
So the integral of y = x4 + 5/x + C
HJ
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