Solve the simultaneous equations: 6x +2y = 2 and 12x - 3y = 18

6x + 2y = 2 and 12x -3y =18 

Start by multiplying the first equation by two in order to balance both equations to have equal numbers of x

12x + 4y = 4 and 12x - 3y = 18

Rearrange both equations so that the x values are on one side on their own and the y values are on the other side 

12x = 4 - 4y and 12x = 3y  + 18

This can now cancel the x values from both equations to form one single equation 

4 -4y = 3y + 18

Rearrange the single equation to work out the value of y

7y = -14 

y = -2

Substitute the value of y back into any of the original two equations to work out the value of x 

x = 1

JH
Answered by Jack H. Maths tutor

3354 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is Pythagoras' Theorem and how do I use it?


Tom thinks of a number. He squares it, adds 3 times the original number and then subtracts 18. The result is 0. What two numbers could Tom have been thinking of?


A cone has a radius of 2 units and a height of 3 units. Devise a simplified equation to find the volume of the cone.


How do you solve a set of three similatenous equations with three unknown variables?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning