Solve the simultaneous equations: 6x +2y = 2 and 12x - 3y = 18

6x + 2y = 2 and 12x -3y =18 

Start by multiplying the first equation by two in order to balance both equations to have equal numbers of x

12x + 4y = 4 and 12x - 3y = 18

Rearrange both equations so that the x values are on one side on their own and the y values are on the other side 

12x = 4 - 4y and 12x = 3y  + 18

This can now cancel the x values from both equations to form one single equation 

4 -4y = 3y + 18

Rearrange the single equation to work out the value of y

7y = -14 

y = -2

Substitute the value of y back into any of the original two equations to work out the value of x 

x = 1

JH
Answered by Jack H. Maths tutor

3530 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What are the possible ways to find the roots from a quadratic equation?


n is an integer greater than 1. Prove algebraically that n^2-2-(n-2)^2 is always an even number


At a concert, the number of men, women and children can be expressed with the following ratio: 6:11:4 There were 6525 more women than men. How many children were at the concert?


Solve these simultaneously to find values for a and b: 6a + b = 16 and 5a - 2b = 19


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning