Express √75 in the form of n√3 , where n is an integer. Using this information, solve the following equation: x√48 = √75 + 3√3 (4 marks)
√75 = 5√3, therefore
x√48 = √75 + 3√3
x√48 = 5√3 + 3√3
x(√16 x √3) = 5√3 + 3√3
4x√3 = 5√3 + 3√3
4x√3 = (5 + 3)√3
4x√3 = 8√3
x√3 = 2√3
x = 2
AT
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