y = (x^2)sin(3x). Find dy/dx

We need to differentiate x2sin(3x). We know how to differentiate (x2) on its own, and how to differentiate sin(3x) on its own. So we can use the Product rule:

dy/dx = (d/dx(x2))sin(3x) + x2(d/dx(sin(3x))

          = (2x)sin(3x) + x2(3cos(3x))

          = 2xsin(3x) + 3x2cos(3x)

Answered by Robert D. Maths tutor

17284 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you do simple integration?


By writing tan x as sin x cos x , use the quotient rule to show that d dx ðtan xÞ ¼ sec2 x .


How do I find the maxima and minima of f(x) = e^(x^2)?


Solve 5x/(2x+1) - 3/(x+1) = 1


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences