(2x+3)/(x-4) - (2x-8)/(2x+1) = 1 Solve for x

Multiply out the denominator, take care to multiply both sides of the equation:

(2x+3)(2x+1) - (2x-8)(x-4) = (2x+1)(x-4)

Expand the brackets, pay attention the the signs when multiplying, expecially the negative between the two sets of brackets on the left hand side.

4x2+2x+6x+3 - (2x2-8x-8x+32)=2x2-7x-4

4x2+2x+6x+3-2x2+8x+8x-32=2x2-7x-4

Group like terms on each side of the equation.

2x2+24x-29=2x2-7x-4

Bring all the terms to one side to leave a quadratic equation equal to 0. Remember to change the sign as you bring a term from one side to the other. 

31x-25 = 0

Rearrange for x

x= 25/31 (=0.81)

Answered by Lucy M. Maths tutor

3008 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation x ^2>=3(x + 6)


Solve for x the equation 1/(3x-6) +2/(x-2) =5


Solve the simultaneous equations: 5x + y = 21 and x - 3y = 9


How do I solve the following question. 'Find the values of x such that 2log3(x) - log3(x-2) = 2'.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences