Use the geometric series formula to find the 9th term in this progression : 12 18 27...

Formula for nth term in a geometric progression = ar^n-1

workings:  

a=12

r=1.5  because 18/12 = 1.5

Thus, using ar^n-1  -->   12 * 1.5^8 = 307.54... or 308 (to 3sf)

(In an ideal scenario question we'd be working with a whole number as the answer, but i created this question in about a minute so couldn't ensure the answer would be a whole number).

 

PF
Answered by Philip F. Maths tutor

8582 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A function is defined by f(x)=x/(2x-2)^(1/2): (a)Determine the maximum domain of f. (b)Differentiate f. (c)Find the inflection points of the function's graph.


What is the equation of the tangent at the point (2,1) of the curve with equation x^2 + 3x + 4.


Let f(x) = 2x^3 + x^2 - 5x + c. Given that f(1) = 0 find the values of c.


Where does the quadratic formula come from?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning