Pseudocode: FUNCTION linearSearch(list, searchTerm): FOR index FROM 0 -> length(list): IF list[index] == searchTerm THEN RETURN index ENDIF ENDLOOP RETURN -1 ENDFUNCTION Complexity: Recognize that the single for loop will access each element in the list once in WCS.If each element is accessed once, then as list grows the time taken (WCS) grows in linear timeTherefore : O(n)What about best case? Average case?Encourage comparison with other known/unknown algorithms