Solve (3x +1)/x + (2x-1)/3 = -3, giving x to two decimal places.

(3x+1)/x +(2x-1)/3 = (2x² + 8x + 3)/3x by cross multiplying.

So equation becomes 2x²+ 8x + 3 = -9x by multiplying both sides by 3x. Adding 9x to both sides gives 2x² + 17x + 3 = 0.

Using a calculator, and the determinant formula -b+-sqrt(b² - 4ac)/2a; where a = 2, b = 17 and c = 3, we get x = -0.18 and -8.32, in two decimal places as required.