Integrate the following expression with respect to x by parts: (2*x)*sin(x)

The integration by parts formula: S:udv/dx = uv -  S:v*du/dx, where S: means "Integral of with respect to x" 

Let 2*x be u and sin(x) be dv/dx

So du/dx =2 and v= -cos(x)

So S:(2x)sin(x) = (2x)(-cos(x)) - S:-cos(x)*2

= -2xcos(x) + 2*sin(x)

= 2sin(x) - 2x*cos(x) +c

DP
Answered by David P. Maths tutor

3003 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate 2x^2 + 4


Express (5x + 3)/((2x - 3)(x + 2)) in partial fractions.


How do I add up the integers from 1 to 1000 without going insane?


Given that x=ln(t) and y=4t^3,a) find an expression for dy/dx, b)and the value of t when d2y/dx2 =0.48. Give your answer to 2 decimal place.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences