How do I calculate the 100th term of the sequence 15, 8, 1, -6...

A sequence means a pattern, so the first thing to do is find the pattern. First try seeing what the difference between the numbers is. 15-7=8, 8-7=1, 1-7=6, so the pattern must be to subtract 7 each time. The first term of the sequence is 15, so let's call that term u1. The next term, u2, is u1-7. The next term, u3, is u2-7 or (u1-7)-7. Let's continue even further, u4=u3-7 or (u1-7-7)-7. Noticing a pattern? u4 is actually u1 minus 3*7. Since 3=4-1, we can see that for u6, we could express it as u1-(6-1)7, or u1-57. So we can formulate the general rule un= u1- (n-1)7, where "n" is any number we choose. This question is asking us to find the 100th term. For the 100th term, n=100. So what is u100? It's u100=u1- (100-1)7, or u100=u1- (997). Since we know u1=15, since this is the first term, and 997= 693, we know that u100= 15-693= -678. 

Answered by Katerina S. Maths tutor

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