By using an integrating factor, solve the differential equation dy/dx + 4y/x = 6x^-3 (6 marks)
Answer : y = 3/x2 + c/x4 Integrating factor is 4/x (1 mark) => I = eintegral (4/x) dx (1 mark) => I = x4 (1 mark). Using the formula, d/dx (x4 y) = 6x (1 mark)=> x4y = integral(6x)dx (1 mark for integrating). Rearranging gets to answer of y=3/x2 + c/x4. Where c is an arbitary constant (1 mark).
MD
Answered by Mark D. • Further Mathematics tutor
7464 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸The function f is defined for x > 0 by f (x) = x^1n x. Obtain an expression for f ′ (x).
Find the four complex roots of the equation z^4 = 8(3^0.5+i) in the form z = re^(i*theta)
What is the complex conjugate?
Express cos(4x) in terms of powers of cos(x)