theta = arctan(5x/2). Using implicit differentiation, find d theta/dx.

First, we must rearrange to give 2tan(θ) = 5x. Differentiate both sides with respect to x: 2sec2(θ)dθ/dx = 5 Use identity sin2(θ) + cos2(θ) = 1, dividing through by cos2(θ), to get 2(1+tan2(θ))dθ/dx=5. From earlier, we know that tan(θ) = 5x/2, so substituting gives 2(1+25x2/4) dθ/dx= 5 dθ/dx = 5/(2+25x2/2)

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Answered by Callum W. Maths tutor

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