Where does the quadratic formulae come from?

The general form of a quadratic equation is, ax2 +bx + c = 0. If we divide all terms by a we get, x2 +(b/a)x + c/a = 0. then by completing the square we get (x+(b/2a))+ c/a - b2/4a2 = 0 which rearanged is, (x+(b/2a))2 = b2/4a-  c/a. We can combine the 2 terms on the left hand side of this equation into, b2-4ac which gives the overall equation,

(x+(b/2a))2 = (b2-4ac) / 4a2. If we then square root both sides we have x+b/2a = sqrt(b2-4ac)/2a. By rearanging again we get x= (sqrt(b2-4ac)-b) / 2a. Which looks like the quadratic formulae, there is a subtlety which is that a square root can be either + or -, i.e. the sqrt(4) is 2 or -2 therefore for our quadratic formulae we have to consider both the postivie and negative terms.

Therefore our overall result reduces to the formulae you are familiar with x= (-b ± sqrt(b2-4ac)) / 2a

Answered by Benjamin O. Maths tutor

3352 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the tangent to the unit circle when x=sqrt(3)/2 (in the first quadrant)


Differentiate expressions of form Ax^b where A and b are constants and x is a variable


How can functions be transformed?


Show how you can rewrite (x+1)(x-2)(x+3) into the form of ax^3 + bx^2 + cx + d


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences