Solve the differential equation: dy/dx = 6x^2 + 4x + 9

dy/dx = 6x2 + 4x + 9

dy = (6x2 + 4x + 9) dx 

integrating gives:

y= (6x3/3) + (4x2/2) + 9x + c

y= 2x3 + 2x2 + 9x + c

If given boundary conditions of y(0)=0 then 

0 = 2(0)3 + 2(0)2 +9(0) +c 

therefore c=0 

so y= 2x3 + 2x2 + 9x

Answered by Jack H. Maths tutor

10456 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

With log base 4, solve log(2x+3) + log(2x+15) = 1 + log(14x+5)


integrate by parts ln(x)/x^3


Find the integral of e^3x/(1+e^x) using the substitution of u=1+e^x


Use chain rule and implicit differentiation to find dy/dx for y^3 = 1 + 3*x^2, then show that they are equal


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences