How would I solve the equation 25^x = 5^(4x+1)?

You would have to rewrite 25 as 5^2 hence 25^x = (5^2)^x = 5^(2*x).

Then 5^(2x) = 5^(4x+1) and therefore 2x = 4x + 1 hence 2x = -1 hence x = -1 / 2. 

MP

Related Maths A Level answers

All answers ▸

A level Maths question - The graph of y=2sin(2x)+1 is rotated 360 degrees about the x-axis to form a solid. Find the volume enclosed by the curve, the co-ordinate axes and the line x=pi/2


Integrate $$\int xe^x \mathop{\mathrm{d}x}$$.


Given the function f(x)=ax^2+bx+c, we are given that it has x-intercepts at (0,0) and (8,0) and a tangent with slope=16 at the point x=2. Find the value of a,b, and c.


The variable x=t^2 and the variable y=2t. What is dy/dx in terms of t?