How would I solve the equation 25^x = 5^(4x+1)?

You would have to rewrite 25 as 5^2 hence 25^x = (5^2)^x = 5^(2*x).

Then 5^(2x) = 5^(4x+1) and therefore 2x = 4x + 1 hence 2x = -1 hence x = -1 / 2. 

MP
Answered by Marius P. Maths tutor

8870 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that y = (1 + 3x^2)^(1/3) , use the chain rule to find dy/dx in terms of x.


Why does the equation x^2+y^2=r^2 form a circle in the Cartesian plane?


Differentiate y=x^(-1/2)-x


Find the tangent to y = x^2 - 4x + 9 at the point (3,15)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning