Solve the simultaneous equations 3x + 2y = 4 and 4x + 5y = 17

3x + 2y = 4 (equation 1) 4x + 5y = 17 (equation 2) Multiply equation 1 by 2.5, giving 7.5x + 5y = 10 (equation 1) 4x + 5y = 17 (equation 2) Subtract equation 2 from equation 1, giving 3.5x = -7 Therefore, x = -2 Substitute x = -2 back into equation 1, so 3(-2) + 2y = 4 -6 + 2y = 4 2y = 10 Therefore y= 5 Final answer: x=-2, y=5

IG
Answered by Isabella G. Maths tutor

4121 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 3x+7y=18 and x+2y=5


Solve 3x^2 = 8x - 2 giving your answers to 2 d.p.


A triangle has sides of 4cm and 5cm with the hypotenuse unknown. What is the length of the unknown side?


ABCD is a rhombus on a graph. B(7,10). AC: y=7-4x. Find an equation for DB in the form tx+py+r=0 where t,p&r are integers.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning