Given that x(a+bx)(a-bx)=25x-4x^3, what is the value of b^(-a)? a,b>0

It's a two part question. First Part Expand the equation the left hand side to get a^(2)*x-b^(2)*x^3 thus comparing co-efficients a^2=25 and b^2=4 thus a= 5 b=2 Second Part Therefore b^(-a) is equal to 2^(-5) which is equal to (1/2)^5 which equals 1/32

Answered by Cameron P. Maths tutor

8072 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I multiply two brackets without missing terms when multiplying?


What is the length of the hypotenuse in the right angled triangle to one decimal place? (a=5cm, b=4cm)


Probability: These 6 coins are in a box - 10p, 10p, 10p, 20p, 20p, 50p. Someone takes 2 coins at random. What is the probability that the total value of the two coins is at least 40p?


Solve 7(k – 3) = 3k – 5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences