Bismuth-208, which has an atomic mass of 208u and 83 protons in the nucleus, decays through the emission of 2 alpha particles and a beta-positive particle. What isotope results from this decay?
20883Bi ==> xyZ + 42a + 42a + 01B x = 208 - 8 = 200 y = 83 - 5 = 78 Proton number = 78 therefore Z = Pt Z= 20078Pt
DL
Related Physics A Level answers
All answers ▸How do I calculate the hydrostatic pressure?
Describe the process of a capacitor charging.
An electron falling from one energy level to another emits a photon of wavelength 550nm. What is the difference between the two energy levels?
Describe and explain the photoelectric effect in terms of photons interacting with the surface of a metal.