Find the equation of the straight line joining points (-1, -4) and (2, 5)

  1. Draw sketch of line 2. Find gradient using m=(y- y1)/(x- x1)= 5--4/2--1=9-3=3 3. Choose one of the points and call it (a,b). I'll pick (2,5) because there's no negaitves. 4. Sub into equation y-b=m(x-a)   y-5= 3(x-2) 5. Simplify  y - 5 = 3x - 6    y = 3x - 1
Answered by Ben M. Maths tutor

7803 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the equation of the line that passes through (2, 4) and (7, -11)


find the coordinates of the single stationary point of the curve with equation y=8x^2 + 2/x


How do we add and subtract negative numbers?


(x+6) and (x+5) are the length and width, respectively, of a rectangle with area 20. Calculate the width of the rectangle.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences