4x-y=3 and 3x-2y=1. Solve these simultaneous equations to find values for x and y.

Equation 1: 4x-y=3  Equation 2: 3x-2y=1

We have to find a common multiple between 4 and 3 so that both equations have the same first value. This means that we can get rid of the x by subtracting the second equation from the first. This will leave us with a simple linear equation with which we can solve to find y and then go on to find x. The lowest common denominator between 4 and 3 is 12. 

3(4x-y)=3x3 -> 12x-3y=9 (Eq. 1)
4(3x-2y)=4x1 -> 12x-8y=4 (Eq. 2)

Eq. 1 - Eq.2 = 12x-12x-3y--8y=9-4 ->  5y=5

hence y=1 and now we have to input the y value into the first (or second) equation to find x

4x-1=3 -> 4x=4 -> x=1

So x=1 and y=1

Answered by Jami H. Maths tutor

10312 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

3 shops sell TVs and all 3 are having sales. Here are the three original prices of the TVs and their discounts: X12: £150 (25%), Teli-vise: £235 (1/2 off), Xpert: £60 (with a year of weekly £8 payments). Which TV is the cheapest once discounted.


Solve the quadratic equation (x^2)-x-12=0 (easy), (x^2)-9=0 (special case), (x^2)+5x-13=0 (quadratic formula)


Solve the simultaneous equations.


How would I find the formula for the nth term of a sequence such as 3, 7, 11, 15, 19?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences