Answers>Maths>IB>Article

a) Let u=(2,3,-1) and w=(3,-1,p). Given that u is perpendicular to w, find the value of p. b)Let v=(1,q,5). Given that modulus v = sqrt(42), find the possible values of q.

a) is perpendicular to w, so =0. This means that 23 + 3(-1) + (-1)*p = 0, so 6-3-p=0, hence p=3. b) The magnitude of v = sqrt(12+q2+52) = sqrt(42). Thus, 1+q2+25 = 42, q2=16, so q is either 4 or -4.

Answered by Cristiana R. Maths tutor

3907 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

What is the area enclosed by the functions x^2 and sqrt(x)?


If the fourth term in an arithmetic sequence is, u4 = 12.5, the tenth is u10 = 27.5. Find the common difference and the 20th term.


A team of four is chosen from six married couples. If a husband and wife cannot both be on the team, in how many ways can the team be formed?


what is the geometrical meaning of the derivative of a function f?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences