When you are given a table of half cells with values for electrode potentials, how do you find the strongest oxidising and reducing agent?

Possibly the easiest way to do this is by thinking about what the value of Electrode Potential means. The more positive the Electrode Potential, the greater the tendency of the species in the equation to be reduced. As we know from the 1st year, species which are reduced are called oxidising agents, hence the strongest oxidising agent may be found in the equation with the greatest value of electrode potential. In redox equations, oxiding agents are always found on the left side of the equilibrium arrow as they are the species being reduced.

This means that the most negative (or least positive) electrode potential is the system in which the species have the greatest tendency to be oxidised. In a redox reaction, the species which is being oxidised is the reducing agent and by convention, it is always found on the right hand side of the equilibrium arrow. Therefore the strongest reducing agent in the table will be on the right hand side of the arrow of the system with the most negative (or least positive) electrode potential.

Answered by James S. Chemistry tutor

6646 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Why does calcium nitrate decompose in a similar way to magnesium nitrate, but require a higher temperature for decomposition?


When 80.0cm^3 of 0.500 M hydrochloric acid was added to 1.75g of impure CaCO3, not all HCl reacts. The unreacted HCl required 22.4 cm^3 of a 0.500 M solution of NaOH for complete reaction. Calculate percentage by mass of CaCO3 in the impure sample.


balance the following equation: Na2O + HCl --> NaCl + H2O


How do buffers work?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences