Answers>Maths>A Level>Article

Find values of y such that: log2(11y–3)–log2(3) –2log2(y) = 1

NB.: Treat all log as log2 for purpose of formatting log(x) - log(z) = log(x/z) alog(b) = log(b^a) log((11y - 3)/3) - log(y^2) = 1 log((11y - 3)/3y^2) = 1 11y - 3 / 3y^2 = 2^1 11y - 3 = 6y^2 6y^2 - 11y + 3 = 0 (3y - 1) (2y - 3) = 0 y = 1/3 or 1.5

Answered by Shrinivas A. • Maths tutor

6324 Views

See similar Maths A Level tutors

Find values of y such that: log2(11y–3)–log2(3) –2log2(y) = 1

Related Maths A Level answers

Show that the integral of tan(x) is ln|sec(x)| + C where C is a constant.

What marks do I need to achieve an A* grade in A-level Maths?

How do I integrate sin^2 (x) dx?

Differentiate with respect to X: x^2 + 2y^2+ 2xy = 2